3(x+2)^2=2x^2+3x-8

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Solution for 3(x+2)^2=2x^2+3x-8 equation: 



3(x+2)^2=2x^2+3x-8

We move all terms to the left:

3(x+2)^2-(2x^2+3x-8)=0

We get rid of parentheses

-2x^2+3(x+2)^2-3x+8=0

We add all the numbers together, and all the variables

-2x^2-3x+3(x+2)^2+8=0

We move all terms containing x to the left, all other terms to the right

-2x^2-3x+3(x+2)^2=-8

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